Results From Simulation of a 0.5-cM Chromosome Segment Containing 10 Markers, With N = 5000
| Length of segment (cM) | Markers in segment | Expected CSH | Observed CSH | CV (%) | t(generations ago) | Nt | 95% confidence interval |
| 0.06 | 2 | 0.083 | 0.090 | 121 | 900 | 4540 | 3581–6098 |
| 0.11 | 3 | 0.043 | 0.046 | 147 | 450 | 4671 | 3363–7477 |
| 0.17 | 4 | 0.029 | 0.024 | 98 | 300 | 6028 | 4759–8184 |
| 0.22 | 5 | 0.022 | 0.023 | 80 | 225 | 4875 | 3949–6347 |
| 0.28 | 6 | 0.018 | 0.013 | 71 | 180 | 6679 | 5449–8610 |
| 0.33 | 7 | 0.015 | 0.011 | 72 | 150 | 6784 | 5411–9074 |
| 0.39 | 8 | 0.013 | 0.008 | 79 | 129 | 8028 | 6072–11,815 |
| 0.44 | 9 | 0.011 | 0.006 | 68 | 113 | 8806 | 6578–13,283 |
| 0.50 | 10 | 0.010 | 0.007 | 63 | 100 | 7377 | 5110–13,194 |
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Results are from analysis of haplotypes after 30,000 simulated generations of breeding under the mutation drift model. The average heterozygosity of the markers was 0.39. The markers were equally spaced, with 0.06 cM between markers.
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↵Calculated as 1/(4Nc + 1), where N = 5000 and c is the length of the segment in morgans.
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↵The average results from 10 replicates. In all replicates, the minimum heterozygosity of the markers was 0.05, as this was the minimum heterozygosity of the markers in the Moffat et al. (2001) data set.
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↵From pooled results over segments of the same length within a replicate and across replicates.
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↵To calculate the 95% confidence intervals forNt, a 95% confidence interval for the observed CSH was calculated as average CSH ± 2SE. Then the upper and lower bounds of CSH were used to calculate the upper and lower bounds of the 95% confidence interval for Nt .
